Integrand size = 22, antiderivative size = 157 \[ \int \frac {(g x)^m \left (a+c x^2\right )^p}{d+e x} \, dx=\frac {x (g x)^m \left (a+c x^2\right )^p \left (1+\frac {c x^2}{a}\right )^{-p} \operatorname {AppellF1}\left (\frac {1+m}{2},-p,1,\frac {3+m}{2},-\frac {c x^2}{a},\frac {e^2 x^2}{d^2}\right )}{d (1+m)}-\frac {e x^2 (g x)^m \left (a+c x^2\right )^p \left (1+\frac {c x^2}{a}\right )^{-p} \operatorname {AppellF1}\left (\frac {2+m}{2},-p,1,\frac {4+m}{2},-\frac {c x^2}{a},\frac {e^2 x^2}{d^2}\right )}{d^2 (2+m)} \]
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Time = 0.09 (sec) , antiderivative size = 157, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.136, Rules used = {973, 525, 524} \[ \int \frac {(g x)^m \left (a+c x^2\right )^p}{d+e x} \, dx=\frac {x (g x)^m \left (a+c x^2\right )^p \left (\frac {c x^2}{a}+1\right )^{-p} \operatorname {AppellF1}\left (\frac {m+1}{2},-p,1,\frac {m+3}{2},-\frac {c x^2}{a},\frac {e^2 x^2}{d^2}\right )}{d (m+1)}-\frac {e x^2 (g x)^m \left (a+c x^2\right )^p \left (\frac {c x^2}{a}+1\right )^{-p} \operatorname {AppellF1}\left (\frac {m+2}{2},-p,1,\frac {m+4}{2},-\frac {c x^2}{a},\frac {e^2 x^2}{d^2}\right )}{d^2 (m+2)} \]
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Rule 524
Rule 525
Rule 973
Rubi steps \begin{align*} \text {integral}& = \left (d x^{-m} (g x)^m\right ) \int \frac {x^m \left (a+c x^2\right )^p}{d^2-e^2 x^2} \, dx-\left (e x^{-m} (g x)^m\right ) \int \frac {x^{1+m} \left (a+c x^2\right )^p}{d^2-e^2 x^2} \, dx \\ & = \left (d x^{-m} (g x)^m \left (a+c x^2\right )^p \left (1+\frac {c x^2}{a}\right )^{-p}\right ) \int \frac {x^m \left (1+\frac {c x^2}{a}\right )^p}{d^2-e^2 x^2} \, dx-\left (e x^{-m} (g x)^m \left (a+c x^2\right )^p \left (1+\frac {c x^2}{a}\right )^{-p}\right ) \int \frac {x^{1+m} \left (1+\frac {c x^2}{a}\right )^p}{d^2-e^2 x^2} \, dx \\ & = \frac {x (g x)^m \left (a+c x^2\right )^p \left (1+\frac {c x^2}{a}\right )^{-p} F_1\left (\frac {1+m}{2};-p,1;\frac {3+m}{2};-\frac {c x^2}{a},\frac {e^2 x^2}{d^2}\right )}{d (1+m)}-\frac {e x^2 (g x)^m \left (a+c x^2\right )^p \left (1+\frac {c x^2}{a}\right )^{-p} F_1\left (\frac {2+m}{2};-p,1;\frac {4+m}{2};-\frac {c x^2}{a},\frac {e^2 x^2}{d^2}\right )}{d^2 (2+m)} \\ \end{align*}
\[ \int \frac {(g x)^m \left (a+c x^2\right )^p}{d+e x} \, dx=\int \frac {(g x)^m \left (a+c x^2\right )^p}{d+e x} \, dx \]
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\[\int \frac {\left (g x \right )^{m} \left (c \,x^{2}+a \right )^{p}}{e x +d}d x\]
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\[ \int \frac {(g x)^m \left (a+c x^2\right )^p}{d+e x} \, dx=\int { \frac {{\left (c x^{2} + a\right )}^{p} \left (g x\right )^{m}}{e x + d} \,d x } \]
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Timed out. \[ \int \frac {(g x)^m \left (a+c x^2\right )^p}{d+e x} \, dx=\text {Timed out} \]
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\[ \int \frac {(g x)^m \left (a+c x^2\right )^p}{d+e x} \, dx=\int { \frac {{\left (c x^{2} + a\right )}^{p} \left (g x\right )^{m}}{e x + d} \,d x } \]
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\[ \int \frac {(g x)^m \left (a+c x^2\right )^p}{d+e x} \, dx=\int { \frac {{\left (c x^{2} + a\right )}^{p} \left (g x\right )^{m}}{e x + d} \,d x } \]
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Timed out. \[ \int \frac {(g x)^m \left (a+c x^2\right )^p}{d+e x} \, dx=\int \frac {{\left (g\,x\right )}^m\,{\left (c\,x^2+a\right )}^p}{d+e\,x} \,d x \]
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